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(D) The compound $A$ is $2,4,4-trimethylpent-1-ene$. Reaction with $O_3, H_2O / Zn$ (reductive ozonolysis) gives formaldehyde $(HCHO)$ as by-product $

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$O_3, H_2O / Zn$ and $KMnO_4 / H^{+}$

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(D) The compound $A$ is $2,4,4-trimethylpent-1-ene$. Reaction with $O_3, H_2O / Zn$ (reductive ozonolysis) gives formaldehyde $(HCHO)$ as by-product $a$ and a ketone. Reaction with $KMnO_4 / H^{+}$ (oxidative cleavage) gives formic acid $(HCOOH)$ as by-product $b$ and a ketone. Formaldehyde $(a)$ on oxidation gives formic acid,which is found in ants. Thus,$X$ is $O_3, H_2O / Zn$ and $Y$ is $KMnO_4 / H^{+}$.

$A$ compound $A$ on reaction with $X$ and $Y$ produces the same major product but different by-products $a$ and $b$. Oxidation of $a$ gives a substance produced by ants.
$X$ and $Y$ respectively are :

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$A$ compound $A$ on reaction with $X$ and $Y$ produces the same major product but different by-products $a$ and $b$. Oxidation of $a$ gives a substance produced by ants.$X$ and $Y$ respectively are :