The reaction of ethene with Cl_2 in a saturat | vedclass

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Question

(A) When ethene $(CH_2=CH_2)$ reacts with $Cl_2$ in the presence of a saturated solution of $KBr$,the reaction proceeds via the formation of a cyclic

Vedclass · Accepted Answer

$ClCH_2CH_2Cl + ClCH_2CH_2Br$

Vedclass · Answer

(A) When ethene $(CH_2=CH_2)$ reacts with $Cl_2$ in the presence of a saturated solution of $KBr$,the reaction proceeds via the formation of a cyclic chloronium ion intermediate. In the presence of $Cl^-$ and $Br^-$ ions,the nucleophilic attack on the cyclic intermediate can occur by either $Cl^-$ or $Br^-$. $1$. Attack by $Cl^-$ leads to the formation of $1,2$-dichloroethane $(ClCH_2CH_2Cl)$. $2$. Attack by $Br^-$ leads to the formation of $1$-bromo-$2$-chloroethane $(ClCH_2CH_2Br)$. Therefore,the reaction yields a mixture of $ClCH_2CH_2Cl$ and $ClCH_2CH_2Br$.

The reaction of ethene with $Cl_2$ in a saturated solution of $KBr$ yields:

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