The product of the reaction is .....

The correct order of the rate of the reaction for the following reaction with respect to nucleophiles is: $CH_{3}Br + Nu^{\ominus} \longrightarrow CH_{3}Nu + Br^{\ominus}$

The major product of the following reaction is
$C_6H_5CH_2CH_3 + (CH_3)_2CHCH_2Cl \xrightarrow{AlCl_3} \text{?}$

Consider the following reactions:
$(a) \; (CH_3)_3CCH(OH)CH_3 \xrightarrow{conc. H_2SO_4} $
$(b) \; (CH_3)_2CHCH(Br)CH_3 \xrightarrow{alc. KOH} $
$(c) \; (CH_3)_2CHCH(Br)CH_3 \xrightarrow{(CH_3)_3CO^{-}K^{+}} $
$(d) \; (CH_3)_2C(OH)CH_2CHO \xrightarrow{\Delta} $
Which of these reaction$(s)$ will not produce Saytzeff product?

For $(i) \, I^{-}, \, (ii) \, Cl^{-}, \, (iii) \, Br^{-}$,the increasing order of nucleophilicity would be

Arrange the leaving group ability of the following groups in decreasing order:
$(I)$ $CH_3-C_6H_4-SO_3^-$,$(II)$ $C_6H_5-SO_3^-$,$(III)$ $N_3^-$,$(IV)$ $Br^-$