The correct order of the rate of the reaction | vedclass

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(D) The rate of an $S_{N}2$ reaction depends on the nucleophilicity of the nucleophile. Nucleophilicity is generally inversely proportional to the sta

Vedclass · Accepted Answer

${}^{-}OH > PhO^{-} > CH_{3}COO^{-} > ClO_{4}^{-}$

Vedclass · Answer

(D) The rate of an $S_{N}2$ reaction depends on the nucleophilicity of the nucleophile. Nucleophilicity is generally inversely proportional to the stability of the anion (conjugate base). The stability order of the given anions is: $ClO_{4}^{-} > CH_{3}COO^{-} > PhO^{-} > {}^{-}OH$. Since nucleophilicity is the reverse of the stability of the anion, the order of nucleophilicity (and thus the rate of reaction) is: ${}^{-}OH > PhO^{-} > CH_{3}COO^{-} > ClO_{4}^{-}$.

The correct order of the rate of the reaction for the following reaction with respect to nucleophiles is: $CH_{3}Br + Nu^{\ominus} \longrightarrow CH_{3}Nu + Br^{\ominus}$

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