In the following reaction,the product (Y) wil | vedclass

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(B) The starting material is $4-bromobenzyl$ chloride $(Cl-CH_2-C_6H_4-Br)$.Step $1$: Reaction with $Mg$ in ether forms the Grignard reagent,$4-chloro

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$1-$chloromethyl$-4-$deuteriobenzene

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(B) The starting material is $4-bromobenzyl$ chloride $(Cl-CH_2-C_6H_4-Br)$.Step $1$: Reaction with $Mg$ in ether forms the Grignard reagent,$4-chloromethylphenylmagnesium$ bromide $(Cl-CH_2-C_6H_4-MgBr)$,which is $(X)$.Step $2$: Reaction of the Grignard reagent with heavy water $(D_2O)$ replaces the $-MgBr$ group with a deuterium atom $(-D)$.The final product $(Y)$ is $1-chloromethyl-4-deuteriobenzene$ $(Cl-CH_2-C_6H_4-D)$.

In the following reaction,the product $(Y)$ will be:

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