$A$ solution of liquids $A$ and $B$ is given. The mole fraction of $A$ in the vapor phase is $x_1$ and in the liquid phase is $x_2$. If $P_A^o$ and $P_B^o$ are the vapor pressures of pure $A$ and $B$ respectively,then the total vapor pressure $P_{total}$ will be:
- A$\frac{x_1}{x_2} P_A^o$
- B$\frac{x_2}{x_1} P_A^o$
- C$\frac{x_1}{x_2} P_B^o$
- D$\frac{x_2}{x_1} P_B^o$
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View SolutionExplain how the solubility of a gaseous solute and the vapour pressure of a liquid solution follow Henry's and Raoult's laws.
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According to Raoult's law,the relative lowering of vapour pressure of a solution of a non-volatile solute is equal to:
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