Explain how the solubility of a gaseous solute and the vapour pressure of a liquid solution follow Henry's and Raoult's laws.

(N/A) According to Raoult's law,the vapour pressure of a volatile component in a solution is given by $p_{i} = x_{i} p_{i}^{0}$.
In the case of a gas dissolved in a liquid,the gas is a volatile component. Its solubility is governed by Henry's law,which states that $P = K_{H} \cdot x$.
Comparing the two equations,we see that the partial pressure of the volatile component (or gas) is directly proportional to its mole fraction $(x)$ in the solution.
The only difference is the proportionality constant: $K_{H}$ in Henry's law and $p_{i}^{0}$ in Raoult's law.
Therefore,Raoult's law can be considered a special case of Henry's law where the proportionality constant $K_{H}$ becomes equal to the pure vapour pressure $p_{i}^{0}$.