What is the B - F bond order in BF_3? | vedclass

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(D) In $BF_3$,the boron atom is electron-deficient and has an empty $p$-orbital. Due to back-bonding from the fluorine lone pairs to the boron $p$-orb

Vedclass · Accepted Answer

$4/3$

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(D) In $BF_3$,the boron atom is electron-deficient and has an empty $p$-orbital. Due to back-bonding from the fluorine lone pairs to the boron $p$-orbital,the $B - F$ bond acquires partial double bond character. The structure is a resonance hybrid of four contributing structures: one with a single bond and three with a double bond. The bond order is calculated as: $	ext{Total number of bonds} / 	ext{Number of bonding positions} = (1 + 1 + 1 + 1) / 3 = 4/3 \approx 1.33$.

What is the $B - F$ bond order in $BF_3$?

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