BCl_3 is planar,while NCl_3 is pyramidal,beca | vedclass

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(A) The geometry of a molecule is determined by the number of bonding pairs and lone pairs of electrons around the central atom according to $VSEPR$ t

Vedclass · Accepted Answer

$BCl_3$ has no lone pair of electrons,whereas $NCl_3$ has one lone pair of electrons.

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(A) The geometry of a molecule is determined by the number of bonding pairs and lone pairs of electrons around the central atom according to $VSEPR$ theory.In $BCl_3$,the central boron atom has $3$ valence electrons,all of which are involved in bonding with $3$ chlorine atoms. It has $0$ lone pairs,resulting in $sp^2$ hybridization and a trigonal planar geometry.In $NCl_3$,the central nitrogen atom has $5$ valence electrons. It forms $3$ bonds with chlorine atoms and retains $1$ lone pair. This results in $sp^3$ hybridization with one lone pair,leading to a pyramidal geometry.

$BCl_3$ is planar,while $NCl_3$ is pyramidal,because...

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