What is the hybridization of the central atom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence el

Vedclass · Accepted Answer

$sp^3$

Vedclass · Answer

(B) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $NH_4^+$,the central atom is $N$ $(V = 5)$,$M = 4$ (four $H$ atoms),$C = 1$,and $A = 0$.$H = \frac{1}{2} (5 + 4 - 1 + 0) = \frac{8}{2} = 4$.$A$ value of $4$ corresponds to $sp^3$ hybridization.

What is the hybridization of the central atom in $NH_4^+$?

Similar Questions

The ion that has $sp^3d^2$ hybridization for the central atom is

Select the systematic diagram which represents the correct change in the bond angle in the hybrid orbital of beryllium.

The hybridization of the central atom of $ClF_3$,$NH_3$,and $SO_3$ are respectively:

What is the hybridization of $C$ atoms in graphite?

Vedclass Test Series

Exam Paper Generator

Online Exam Module