Among the triatomic molecules/ions,BeCl_2, N_ | vedclass

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(D) The geometries and hybridizations are as follows:$1. BeCl_2$: $sp$ hybridization,linear,no $d$-orbital contribution.$2. N_3^{-}$: $sp$ hybridizati

Vedclass · Accepted Answer

$4$

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(D) The geometries and hybridizations are as follows:$1. BeCl_2$: $sp$ hybridization,linear,no $d$-orbital contribution.$2. N_3^{-}$: $sp$ hybridization,linear,no $d$-orbital contribution.$3. N_2O$: $sp$ hybridization,linear,no $d$-orbital contribution.$4. NO_2^{+}$: $sp$ hybridization,linear,no $d$-orbital contribution.$5. O_3$: $sp^2$ hybridization,bent.$6. SCl_2$: $sp^3$ hybridization,bent.$7. I_3^{-}$: $sp^3d$ hybridization,linear,involves $d$-orbital.$8. ICl_2^{-}$: $sp^3d$ hybridization,linear,involves $d$-orbital.$9. XeF_2$: $sp^3d$ hybridization,linear,involves $d$-orbital.Thus,the molecules/ions that are linear and do not involve $d$-orbitals in hybridization are $BeCl_2, N_3^{-}, N_2O$,and $NO_2^{+}$.The total count is $4$.

$Column\, I$	$Column\, II$
$(A)\, XeF_6$	$(i)\, \text{Distorted octahedral}$
$(B)\, XeO_3$	$(ii)\, \text{Square planar}$
$(C)\, XeOF_4$	$(iii)\, \text{Pyramidal}$
$(D)\, XeF_4$	$(iv)\, \text{Square pyramidal}$

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