In the reaction P_4 + 3KOH + 3H_2O to PH_3 + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the reaction $P_4 + 3KOH + 3H_2O 	o PH_3 + 3KH_2PO_2$,the oxidation state of phosphorus changes as follows:$1$. In $P_4$,the oxidation state o

Vedclass · Accepted Answer

both oxidized and reduced

Vedclass · Answer

(C) In the reaction $P_4 + 3KOH + 3H_2O 	o PH_3 + 3KH_2PO_2$,the oxidation state of phosphorus changes as follows:$1$. In $P_4$,the oxidation state of $P$ is $0$.$2$. In $PH_3$,the oxidation state of $P$ is $-3$ (reduction).$3$. In $KH_2PO_2$,the oxidation state of $P$ is $+1$ (oxidation).Since phosphorus is simultaneously oxidized and reduced,this is a disproportionation reaction.

In the reaction $P_4 + 3KOH + 3H_2O \to PH_3 + 3KH_2PO_2$,phosphorus is .........

Similar Questions

$3ClO^- \to ClO_3^- + 2Cl^-$; This reaction is an example of which of the following?

$PhCHO \xrightarrow{OH^{-}} PhCH_2OH + PhCOO^{-}$
This reaction is an example of -

The disproportionation products of $ortho-phosphorous$ acid are

The reaction of white phosphorus with aqueous $NaOH$ gives phosphine along with another phosphorus-containing compound. The reaction is known as:

Which of the following acts as both an oxidizing and a reducing agent?

Vedclass Test Series

Exam Paper Generator

Online Exam Module