Determine the hybridization of the sulfur ato | vedclass

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(A) The hybridization of an atom can be calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons of

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$sp^2$

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(A) The hybridization of an atom can be calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the charge on the cation,and $A$ is the charge on the anion.For $SO_3$,the central atom is sulfur $(S)$.Valence electrons of $S$ $(V)$ = $6$.Number of monovalent atoms $(M)$ = $0$ (since oxygen is divalent).$H = \frac{1}{2}(6 + 0) = 3$.$A$ hybridization value of $3$ corresponds to $sp^2$ hybridization.Thus,the sulfur atom in $SO_3$ is $sp^2$ hybridized.

Determine the hybridization of the sulfur atom in the $SO_3$ molecule.

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