F_2 is a stronger oxidizing agent than Br_2 d | vedclass

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(A) The oxidizing power of a halogen depends on the standard electrode potential $(E^\circ)$.$F_2$ has a very high positive standard electrode potenti

Vedclass · Accepted Answer

Small size of fluorine

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(A) The oxidizing power of a halogen depends on the standard electrode potential $(E^\circ)$.$F_2$ has a very high positive standard electrode potential $(+2.87 \ V)$ compared to $Br_2$ $(+1.09 \ V)$.This is primarily due to the low bond dissociation enthalpy of the $F-F$ bond and the high hydration enthalpy of the $F^-$ ion.However,the small size of the fluorine atom leads to high electron-electron repulsion in the $F^-$ ion,which is a significant factor in its thermodynamic properties,but the overall oxidizing strength is governed by the sum of atomization,ionization/electron gain,and hydration energies.Among the given options,the small size of the fluorine atom is the fundamental reason for its unique properties,including its high oxidizing power.

$F_2$ is a stronger oxidizing agent than $Br_2$ due to..........

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