Sodium metal reacts with Al_2O_3 at high temp | vedclass

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Question

(B) The reaction of sodium metal with $Al_2O_3$ at high temperature produces sodium oxide $(Na_2O)$ and aluminum metal: $6Na + Al_2O_3 \rightarrow 3Na

Vedclass · Accepted Answer

$Na_2CO_3$

Vedclass · Answer

(B) The reaction of sodium metal with $Al_2O_3$ at high temperature produces sodium oxide $(Na_2O)$ and aluminum metal: $6Na + Al_2O_3 \rightarrow 3Na_2O + 2Al$. Here,$X$ is $Na_2O$. When $Na_2O$ reacts with $CO_2$ in the presence of water,it forms sodium carbonate $(Na_2CO_3)$: $Na_2O + CO_2 \rightarrow Na_2CO_3$. Thus,$Y$ is $Na_2CO_3$.

Sodium metal reacts with $Al_2O_3$ at high temperature to give a sodium compound $X$. Compound $X$ reacts with $CO_2$ in water to give $Y$. What is $Y$?

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