Which of the following compounds is the most | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(EWG)$

Vedclass · Accepted Answer

$p-$Nitrophenol

Vedclass · Answer

(C) The acidity of phenols is determined by the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(EWG)$ increase acidity by stabilizing the negative charge on the phenoxide ion through inductive and resonance effects. Electron-donating groups $(EDG)$ decrease acidity by destabilizing the phenoxide ion. Comparing the substituents: $1$. $-CH_3$ (in $p-$Cresol) is an $EDG$ (+$I$ effect). $2$. $-Cl$ (in $p-$Chlorophenol) is an $EWG$ (-$I$ effect). $3$. $-NO_2$ (in $p-$Nitrophenol) is a strong $EWG$ (-$I$ and -$M$ effects). $4$. $-NH_2$ (in $p-$Aminophenol) is an $EDG$ (+$M$ effect). Since the $-NO_2$ group provides the strongest electron-withdrawing effect,$p-$Nitrophenol is the most acidic among the given compounds.

Which of the following compounds is the most acidic?

Similar Questions

Explain why nucleophilic substitution reactions are not very common in phenol.

How can $2,4,6$-trinitrophenol (picric acid) and benzoic acid be distinguished?

The major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$

Which of the following is the correct decreasing order of acidic strength for the compounds listed below?
$I$: $p$-chlorophenol
$II$: $p$-Cresol
$III$: $p$-nitrophenol
$IV$: $p$-methoxyphenol

The most suitable method for the separation of a $1:1$ mixture of $o-$ and $p-$ nitrophenols is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module