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Question

(C) The reaction sequence proceeds as follows:$1$. Aniline reacts with $NaNO_2/HCl$ at $273-278 \ K$ to form benzene diazonium chloride.$2$. Hydrolysi

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$2,4,6-$Tribromoanisole

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(C) The reaction sequence proceeds as follows:$1$. Aniline reacts with $NaNO_2/HCl$ at $273-278 \ K$ to form benzene diazonium chloride.$2$. Hydrolysis with warm $H_2O$ converts the diazonium salt into phenol.$3$. Phenol reacts with excess $Br_2$ (bromine water) to undergo electrophilic aromatic substitution,yielding $2,4,6$-tribromophenol.$4$. Treatment with $NaOH$ converts the phenol into sodium phenoxide ($2,4,6$-tribromophenoxide).$5$. Finally,reaction with $CH_3I$ (Williamson ether synthesis) yields $2,4,6$-tribromoanisole as the final product.

The major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$

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The major product of the following reaction sequence is:Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$