An organic compound with the molecular formul | vedclass

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Question

(C) The molecular formula $C_4H_{10}O$ corresponds to either an alcohol or an ether. Since the compound does not react with sodium metal,it must be an

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$1-$Methoxypropane

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(C) The molecular formula $C_4H_{10}O$ corresponds to either an alcohol or an ether. Since the compound does not react with sodium metal,it must be an ether. Among the given options,$1-$Methoxypropane $(CH_3-O-CH_2-CH_2-CH_3)$ is an ether. When $1-$Methoxypropane reacts with excess $HI$,it undergoes cleavage: $CH_3-O-CH_2-CH_2-CH_3 + 2HI \rightarrow CH_3I + CH_3CH_2CH_2I + H_2O$. This reaction produces two types of alkyl halides: methyl iodide $(CH_3I)$ and $1-$iodopropane $(CH_3CH_2CH_2I)$.

An organic compound with the molecular formula $C_4H_{10}O$ does not react with sodium metal and produces only two types of halides upon reaction with excess $HI$. What is the compound?

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