(C) Let the tennis ball bounce with an initial velocity $u$. It will rise to a height $h$ where its final velocity becomes $0$. Using the equation of

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If the $Assertion$ is correct but $Reason$ is incorrect.

(C) Let the tennis ball bounce with an initial velocity $u$. It will rise to a height $h$ where its final velocity becomes $0$. Using the equation of motion $v^2 - u^2 = 2as$,we get:$0^2 - u^2 = 2(-g')h$,where $g'$ is the acceleration due to gravity on the hill.Therefore,$h = \frac{u^2}{2g'}$.Since the acceleration due to gravity on the hill $(g')$ is less than that on the surface of the earth $(g)$ due to the increase in altitude,the height $h$ will be greater on the hill.Thus,the $Assertion$ is correct,but the $Reason$ is incorrect because $g'$ is actually less than $g$.

Class 11 Physics Gravitation Acceleration Due to Gravity and its Variation

Medium

$Assertion$ : $A$ tennis ball bounces higher on hills than in plains.
$Reason$ : Acceleration due to gravity on the hill is greater than that on the surface of earth.

AIIMS 2009 All AIIMS

A
If both $Assertion$ and $Reason$ are correct and the $Reason$ is a correct explanation of the $Assertion$.
B
If both $Assertion$ and $Reason$ are correct but $Reason$ is not a correct explanation of the $Assertion$.
C
If the $Assertion$ is correct but $Reason$ is incorrect.
D
If both the $Assertion$ and $Reason$ are incorrect.

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Gravitation

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Acceleration Due to Gravity and its Variation

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$Assertion$ : $A$ tennis ball bounces higher on hills than in plains.$Reason$ : Acceleration due to gravity on the hill is greater than that on the surface of earth.

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The weight of a body on the earth is $400\,N$. Then weight of the body when taken to a depth half of the radius of the earth will be ............ $N$.

The acceleration due to gravity at a height $1\, km$ above the earth is the same as at a depth $d$ below the surface of earth. Then $d = $ ......... $km$

In the provided figure of the Earth,the value of acceleration due to gravity is the same at points $A$ and $C$,but it is smaller than its value at point $B$ (surface of the Earth). The value of $OA : AB$ is $x : y$. The value of $x$ is $\ldots \ldots \ldots$

Considering Earth to be a sphere of radius $R$ having uniform density $\rho$,the value of acceleration due to gravity $g$ in terms of $R$,$\rho$,and $G$ is:

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$Assertion$ : $A$ tennis ball bounces higher on hills than in plains.
$Reason$ : Acceleration due to gravity on the hill is greater than that on the surface of earth.