Assertion : A quick collision between two bod | vedclass

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(A) According to Newton's second law,the impulsive force $F$ is given by $F = \frac{\Delta p}{\Delta t}$,where $\Delta p$ is the change in momentum an

Vedclass · Accepted Answer

If both $Assertion$ and $Reason$ are correct and the $Reason$ is a correct explanation of the $Assertion$.

Vedclass · Answer

(A) According to Newton's second law,the impulsive force $F$ is given by $F = \frac{\Delta p}{\Delta t}$,where $\Delta p$ is the change in momentum and $\Delta t$ is the time duration of the collision.In a quick collision,the time duration $\Delta t$ is very small.Since the change in momentum $\Delta p$ is the same for both cases (as initial and final velocities are identical),the force $F$ is inversely proportional to $\Delta t$ $(F \propto \frac{1}{\Delta t})$.Therefore,for a smaller $\Delta t$,the force $F$ is much larger,making the collision more violent.The rate of change of momentum is defined as $\frac{\Delta p}{\Delta t}$,which is exactly the force $F$.Since $\Delta t$ is smaller in the first case,the rate of change of momentum is indeed greater.Thus,both the $Assertion$ and $Reason$ are correct,and the $Reason$ is the correct explanation of the $Assertion$.

$Assertion$ : $A$ quick collision between two bodies is more violent than a slow collision,even when the initial and final velocities are identical.
$Reason$ : The rate of change of momentum is greater in the first case.

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$Assertion$ : $A$ quick collision between two bodies is more violent than a slow collision,even when the initial and final velocities are identical.$Reason$ : The rate of change of momentum is greater in the first case.