Write about the oxidation of alcohols.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Oxidation: The oxidation of alcohols involves the breaking of $C-H$ and $O-H$ bonds to form a carbon-oxygen double bond $(C=O)$.
Oxidation/Dehydrogenation: In this process,$C-H$ and $O-H$ bonds are broken and dihydrogen $(H_2)$ is released,which is why this process is called dehydrogenation.
The products of oxidation depend on the oxidizing agents used and the type of alcohol.
$(b)$ Oxidation of primary alcohols: Depending on the oxidizing agent used,$1^{\circ}$ alcohols are oxidized to aldehydes,which are further oxidized to carboxylic acids.
$(i)$ $1^{\circ}$-Alcohol $\rightarrow$ Carboxylic acid: Strong oxidizing agents like potassium permanganate $(KMnO_4)$ are used to obtain carboxylic acids directly from $1^{\circ}$-alcohol compounds.

Explore More

Similar Questions

Identify the product $B$ in the following series of reactions.
$CH_3-CH_2-CH_2-OH$ $\xrightarrow{Al_2 O_3, 623 \ K} A$ $\xrightarrow[(ii) H_2 O]{(i) \text{conc. } H_2 SO_4} B$

What is the product formed when phenylmagnesium bromide reacts with methanol?

The major product of the following reaction is:

$CH_3MgI$ will give methane with

When alcohol reacts with concentrated $H_2SO_4$,the intermediate compound formed is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo