If vec{A} + vec{B} = vec{C} and |vec{A}| + |v | vedclass

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(B) The magnitude of the resultant vector $\vec{C}$ is given by $|\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}| \cos 	heta}$,where

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They are in the same direction.

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(B) The magnitude of the resultant vector $\vec{C}$ is given by $|\vec{C}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}| \cos 	heta}$,where $	heta$ is the angle between $\vec{A}$ and $\vec{B}$.Given that $|\vec{A}| + |\vec{B}| = |\vec{C}|$,we square both sides: $(|\vec{A}| + |\vec{B}|)^2 = |\vec{C}|^2$.$|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}| = |\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}| \cos 	heta$.This simplifies to $2|\vec{A}||\vec{B}| = 2|\vec{A}||\vec{B}| \cos 	heta$,which implies $\cos 	heta = 1$.Therefore,$	heta = 0^{\circ}$,meaning $\vec{A}$ and $\vec{B}$ are in the same direction.

If $\vec{A} + \vec{B} = \vec{C}$ and $|\vec{A}| + |\vec{B}| = |\vec{C}|$,what can be said about the direction of these vectors?

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