Calculate the molar mass of naturally occurring argon from the data given in the following table:
Isotope Molar Mass $(g \ mol^{-1})$ Abundance $^{36}Ar$ $35.96755$ $0.337 \%$ $^{38}Ar$ $37.96272$ $0.063 \%$ $^{40}Ar$ $39.9624$ $99.600 \%$
| Isotope | Molar Mass $(g \ mol^{-1})$ | Abundance |
| $^{36}Ar$ | $35.96755$ | $0.337 \%$ |
| $^{38}Ar$ | $37.96272$ | $0.063 \%$ |
| $^{40}Ar$ | $39.9624$ | $99.600 \%$ |
The average molar mass is calculated using the formula: $\overline{A} = \sum (f_i \times A_i)$
$\overline{A} = (0.00337 \times 35.96755) + (0.00063 \times 37.96272) + (0.99600 \times 39.9624)$
$\overline{A} = 0.12121 + 0.02392 + 39.80255$
$\overline{A} = 39.94768 \approx 39.948 \ g \ mol^{-1}$
$\overline{A} = (0.00337 \times 35.96755) + (0.00063 \times 37.96272) + (0.99600 \times 39.9624)$
$\overline{A} = 0.12121 + 0.02392 + 39.80255$
$\overline{A} = 39.94768 \approx 39.948 \ g \ mol^{-1}$
Explore More
Similar Questions
The present atomic weight scale is based on
Easy
View SolutionWhat is the mass of one molecule of the compound $C_{60}H_{122}$ in grams?
Medium
View SolutionThe unit of atomic mass,$amu$ is replaced by $u$,here $u$ stands for
One liter of hard water contains $12.00 \, mg$ of $Mg^{2+}$. How many milliequivalents of washing soda are required to remove its hardness?
Difficult
View SolutionIf $A$,$E$,$M$,and $n$ represent atomic mass,equivalent mass,molecular mass,and valency of an element respectively,which of the following relations is correct?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo