What is the mass of one molecule of the compo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molecular formula of the compound is $C_{60}H_{122}$.First,calculate the molar mass of $C_{60}H_{122}$:$M = (60 	imes 12.01) + (122 	imes 1.

Vedclass · Accepted Answer

$1.4 	imes 10^{-21}$

Vedclass · Answer

(D) The molecular formula of the compound is $C_{60}H_{122}$.First,calculate the molar mass of $C_{60}H_{122}$:$M = (60 	imes 12.01) + (122 	imes 1.008) = 720.6 + 122.976 = 843.576 \ g/mol$.Using the Avogadro constant $(N_A = 6.022 	imes 10^{23} \ mol^{-1})$,the mass of one molecule is given by:$	ext{Mass} = \frac{	ext{Molar mass}}{N_A} = \frac{843.576}{6.022 	imes 10^{23}} \approx 1.4008 	imes 10^{-21} \ g$.Thus,the mass of one molecule is approximately $1.4 	imes 10^{-21} \ g$.

What is the mass of one molecule of the compound $C_{60}H_{122}$ in grams?

Similar Questions

Sulphur forms the chlorides $S_2Cl_2$ and $SCl_2$. The equivalent mass of sulphur in $SCl_2$ is $...$ $g/mol$.

The heaviest atom amongst the following is

The equivalent mass of a divalent metal is $32$. What is the molar mass of its nitrate salt?

An oxide of an element contains $20 \%$ oxygen by weight. Calculate the equivalent weight of the element.

Upon fully dissolving $2.0 \ g$ of a metal in sulphuric acid,$6.8 \ g$ of the metal sulphate is formed. The equivalent weight of the metal is $...... \ g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module