Calculate the energy of 1 mol of photons hav | vedclass

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Question

(A) The energy of one photon is given by $E = h 
u$. For $1 \ mol$ of photons,the energy is $E = N_A 	imes h 	imes 
u$. Given: $N_A = 6.022 	imes

Vedclass · Accepted Answer

$159.0 \ kJ \ mol^{-1}$

Vedclass · Answer

(A) The energy of one photon is given by $E = h 
u$. For $1 \ mol$ of photons,the energy is $E = N_A 	imes h 	imes 
u$. Given: $N_A = 6.022 	imes 10^{23} \ mol^{-1}$,$h = 6.626 	imes 10^{-34} \ J \cdot s$,and $
u = 4.0 	imes 10^{14} \ Hz$. $E = (6.022 	imes 10^{23}) 	imes (6.626 	imes 10^{-34}) 	imes (4.0 	imes 10^{14}) \ J \ mol^{-1}$. $E \approx 159529 \ J \ mol^{-1} \approx 159.5 \ kJ \ mol^{-1}$. Rounding to the nearest provided option,the answer is $159.0 \ kJ \ mol^{-1}$.

Calculate the energy of $1 \ mol$ of photons having a frequency of $4.0 \times 10^{14} \ Hz$.

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