Match the properties given in List-$I$ with the elements given in List-$II$:
List-$I$ (Property) List-$II$ (Element)
$(A)$ Lanthanoid showing $+4$ oxidation state $(i)$ $Pm$
$(B)$ Lanthanoid showing $+2$ oxidation state $(ii)$ $Ce$
$(C)$ Radioactive lanthanoid $(iii)$ $Lu$
$(D)$ Lanthanoid with $4f^7$ configuration in $+3$ state $(iv)$ $Eu$
$(E)$ Lanthanoid with $4f^{14}$ configuration in $+3$ state $(v)$ $Gd$
- $(vi)$ $Dy$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) $(A) \rightarrow (ii)$ ($Ce^{4+}$ is stable due to noble gas configuration).
$(B) \rightarrow (iv)$ ($Eu^{2+}$ is stable due to $4f^7$ configuration).
$(C) \rightarrow (i)$ ($Pm$ is the only radioactive lanthanoid).
$(D) \rightarrow (v)$ ($Gd^{3+}$ has $4f^7$ configuration).
$(E) \rightarrow (iii)$ ($Lu^{3+}$ has $4f^{14}$ configuration).

Explore More

Similar Questions

Determine the correct $(T)$ and incorrect $(F)$ statements from the following:
$(a)$ The symbol for Lanthanum is $La$.
$(b)$ The name of the element $Lu$ is Lanthanum.
$(c)$ The electronic configuration of $La^{3+}$ and $Ce^{4+}$ contains $4f^0$.

Difficult
View Solution

Which of the following statements is incorrect?

Which lanthanoid from the following exhibits $f^{14}$ configuration in the $+3$ oxidation state?

Compare the chemistry of the actinoids with that of lanthanoids with reference to:
$(i)$ electronic configuration
$(ii)$ oxidation states and
$(iii)$ chemical reactivity.

Provide the primary differences (comparison) between Lanthanoids and Actinoids.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo