Complete the following reaction:CH_3CH_2-O-C( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of an ether with concentrated $HI$ proceeds via an $S_N1$ mechanism when one of the alkyl groups is tertiary.In the given ether,$CH_3

Vedclass · Accepted Answer

$CH_3CH_2OH + CH_3-CI(CH_3)-CH_2CH_3$

Vedclass · Answer

(A) The reaction of an ether with concentrated $HI$ proceeds via an $S_N1$ mechanism when one of the alkyl groups is tertiary.In the given ether,$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3$,the group attached to the oxygen is a tertiary alkyl group ($2$-methyl$-2-$butyl group).The protonation of the ether oxygen by $HI$ forms an oxonium ion.Then,the $C-O$ bond breaks to form a stable tertiary carbocation $(CH_3)_2C^+-CH_2CH_3$ and ethanol $(CH_3CH_2OH)$.The iodide ion $(I^-)$ then attacks the tertiary carbocation to form $2-$iodo$-2-$methylbutane.Thus,the products are ethanol $(CH_3CH_2OH)$ and $2-$iodo$-2-$methylbutane $(CH_3-CI(CH_3)-CH_2CH_3)$.

Column-$I$ (Product)	Column-$II$ (Reagent)
$A$. Mainly $p$-bromoanisole	$i$. Anhydrous $AlCl_3$,$CH_3COCl$
$B$. $4$-nitroanisole	$ii$. $CH_3Cl$,anhydrous $AlCl_3$ in $CS_2$
$C$. $4$-methoxytoluene	$iii$. $Br_2$ in ethanoic acid
$D$. $4$-methoxyacetophenone	$iv$. Mixture of conc. $H_2SO_4$ and $HNO_3$

Complete the following reaction:
$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3 + \text{conc. } HI \to (?)$

Similar Questions

What is $Y$ in the following reaction?
$C_2H_5I + NaOC_2H_5 \longrightarrow X + NaI$
$X + 2HI \xrightarrow{\Delta} 2Y + H_2O$

Give the major product formed by heating $CH_3-CH_2-CH_2-O-C(CH_3)_2-CH_2-CH_3$ with $HI$.

When alkyl halide is heated with dry $Ag_2O$,it produces

The reaction of methyl chloride with silver acetate yields $................$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Complete the following reaction:$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3 + \text{conc. } HI \to (?)$