Different planets have masses M_1, M_2, M_3 a | vedclass

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(A) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$,where $M$ is the mass and $R$ is the radius of the pla

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$M_3 > M_1 > M_2$

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(A) The acceleration due to gravity on the surface of a planet is given by $g = \frac{GM}{R^2}$,where $M$ is the mass and $R$ is the radius of the planet.From the graph,we observe that at the surfaces,$g_1 = g_3 > g_2$.For $g_1 = g_3$,we have $\frac{GM_1}{R_1^2} = \frac{GM_3}{R_3^2}$,which implies $\frac{M_1}{R_1^2} = \frac{M_3}{R_3^2}$.Since $R_1 Now,comparing $g_1$ and $g_2$,we have $g_1 > g_2$,so $\frac{GM_1}{R_1^2} > \frac{GM_2}{R_2^2}$.Given the graph,$R_1  g_2$,which leads to $M_1 > M_2$.Combining these results,we get $M_3 > M_1 > M_2$.

Different planets have masses $M_1, M_2, M_3$ and radii $R_1, R_2, R_3$ respectively. The acceleration due to gravity on their surfaces are $g_1, g_2, g_3$ respectively. Based on the given graph,arrange their masses in descending order.

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