Match Column-$I$ with Column-$II$.
Column-$I$Column-$II$
$(1)$ $\frac{{{m_1}{m_2}}}{{{m_1} + {m_2}}}$$(a)$ Reduced mass of a two-particle system
$(2)$ $\frac{{{r_1} + {r_2}}}{2}$$(b)$ Position vector of the center of mass for a system of two equal masses

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) For $(1)$, the reduced mass $\mu$ of a system of two particles with masses $m_1$ and $m_2$ is defined as $\mu = \frac{m_1 m_2}{m_1 + m_2}$. Thus, $(1)$ matches with $(a)$.
For $(2)$, the center of mass $R_{cm}$ of a system of two particles with masses $m_1$ and $m_2$ at positions $r_1$ and $r_2$ is given by $R_{cm} = \frac{m_1 r_1 + m_2 r_2}{m_1 + m_2}$. If $m_1 = m_2 = m$, then $R_{cm} = \frac{m(r_1 + r_2)}{2m} = \frac{r_1 + r_2}{2}$. Thus, $(2)$ matches with $(b)$.
The correct matching is $(1-a, 2-b)$.

Explore More

Similar Questions

The centre of mass of a non-uniform rod of length $L$ whose mass per unit length $\lambda$ varies as $\lambda = \frac{k x^3}{L^3}$ (where $k$ is a constant and $x$ is the distance of any point on the rod from one end) is at a distance from the same end equal to:

Difficult
View Solution

Three masses of $2\,kg$,$4\,kg$,and $4\,kg$ are placed at the three points $(1, 0, 0)$,$(1, 1, 0)$,and $(0, 1, 0)$ respectively. The position vector of its center of mass is:

Difficult
View Solution

$A$ $T$-shaped object of uniform thickness and same material with dimensions shown in the figure,is lying on a smooth floor. $A$ force $\vec F$ is applied at the point $P$ parallel to $AB$,such that the object has only the translation motion without rotation. Find the location of $P$ with respect to $C$.

Difficult
View Solution

Two particles of masses $200 \ g$ and $500 \ g$ are moving with velocities $10 \ \hat{i} \ m/s$ and $3 \ \hat{i} + 5 \ \hat{j} \ m/s$ respectively. The velocity of the center of mass of the system is:

Difficult
View Solution

$A$ rigid body consists of a $3 \ kg$ mass and a $2 \ kg$ mass connected by a massless rod. The $3 \ kg$ mass is at $\vec{r}_1 = (2 \hat{i} + 5 \hat{j}) \ m$ and the $2 \ kg$ mass is at $\vec{r}_2 = (4 \hat{i} + 2 \hat{j}) \ m$. Find the length of the rod and the coordinates of the center of mass.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo