What is the wavelength of an electron? What does it indicate?
(N/A) The wavelength of an electron is calculated using the de Broglie relation $\lambda = \frac{h}{mv}$.
This wavelength is relatively long compared to the wavelength of matter and indicates that the electron possesses wave-particle duality,specifically exhibiting wave nature.
This wavelength is relatively long compared to the wavelength of matter and indicates that the electron possesses wave-particle duality,specifically exhibiting wave nature.
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Similar Questions
Calculate the wavelength of an electron if its mass is $9.1 \times 10^{-31} \, kg$,its velocity is $1/10$ of the speed of light,and the value of Planck's constant $h$ is $6.626 \times 10^{-34} \, J \cdot s$.
Medium
View SolutionIf the kinetic energy of an electron of mass $9.0 \times 10^{-31} \ kg$ is $8.0 \times 10^{-25} \ J$,the wavelength of this electron in $nm$ is
The wavelength of an electron and a neutron will become equal when the velocity of the electron is $x$ times the velocity of the neutron. The value of $x$ is (Nearest Integer). (Mass of electron is $9.1 \times 10^{-31} \ kg$ and mass of neutron is $1.6 \times 10^{-27} \ kg$)
The wavelength of the electron in the ground state of a hydrogen atom is $y \ \mathring{A}$. What is the wavelength of the electron in the fourth orbit of $He^{+}$ ion (in $\mathring{A}$)?
DifficultAP EAMCET 2022
View Solution$A$ $20 \, g$ object is moving with a velocity of $100 \, ms^{-1}$. The de Broglie wavelength (in $m$) of the object is [Planck's constant $h = 6.626 \times 10^{-34} \, Js$]
DifficultKVPY 2017
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