Identify the neutral atoms having the outermo | vedclass

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Question

(A) For the configuration $2p^4$: The total electrons are $1s^2 2s^2 2p^4$,so $Z = 8$,which corresponds to Oxygen $(O)$.For the configuration $3s^2$:

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$O, Mg, N$

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(A) For the configuration $2p^4$: The total electrons are $1s^2 2s^2 2p^4$,so $Z = 8$,which corresponds to Oxygen $(O)$.For the configuration $3s^2$: The total electrons are $1s^2 2s^2 2p^6 3s^2$,so $Z = 12$,which corresponds to Magnesium $(Mg)$.For the configuration $2p^3$: The total electrons are $1s^2 2s^2 2p^3$,so $Z = 7$,which corresponds to Nitrogen $(N)$.Therefore,the atoms are $O, Mg, N$.

Identify the neutral atoms having the outermost electronic configurations as $2p^4$,$3s^2$,and $2p^3$ respectively.

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