Which of the following species are isoelectro | vedclass

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(A, B) Isoelectronic species are those that contain the same number of electrons.$1$. For $Na^{+}$ $(Z=11)$,number of electrons $= 11 - 1 = 10$.$2$. F

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$K^{+}, Ca^{2+}, S^{2-}, Ar$

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(A, B) Isoelectronic species are those that contain the same number of electrons.$1$. For $Na^{+}$ $(Z=11)$,number of electrons $= 11 - 1 = 10$.$2$. For $Mg^{2+}$ $(Z=12)$,number of electrons $= 12 - 2 = 10$.$3$. For $K^{+}$ $(Z=19)$,number of electrons $= 19 - 1 = 18$.$4$. For $Ca^{2+}$ $(Z=20)$,number of electrons $= 20 - 2 = 18$.$5$. For $S^{2-}$ $(Z=16)$,number of electrons $= 16 + 2 = 18$.$6$. For $Ar$ $(Z=18)$,number of electrons $= 18$.Thus,$Na^{+}$ and $Mg^{2+}$ are isoelectronic ($10$ electrons),and $K^{+}, Ca^{2+}, S^{2-},$ and $Ar$ are isoelectronic ($18$ electrons).

Species	Number of Electrons
$(i) Be^{2+}$	$(a) 0$
$(ii) H^{+}$	$(b) 10$
$(iii) Na^{+}$	$(c) 2$
$(iv) Mg^{+}$	$(d) 11$

Which of the following species are isoelectronic (i.e.,have the same number of electrons)?
$Na^{+}, K^{+}, Mg^{2+}, Ca^{2+}, S^{2-}, Ar$

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Match the following species with the correct number of electrons present in them:

Species Number of Electrons

$(i) Be^{2+}$ $(a) 0$

$(ii) H^{+}$ $(b) 10$

$(iii) Na^{+}$ $(c) 2$

$(iv) Mg^{+}$ $(d) 11$

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Which of the following species are isoelectronic (i.e.,have the same number of electrons)?$Na^{+}, K^{+}, Mg^{2+}, Ca^{2+}, S^{2-}, Ar$