Identify which of the following sets of quantum numbers are not possible and explain why.
$(a) n = 0, l = 0, m_l = 0, m_s = +1/2$
$(b) n = 1, l = 0, m_l = 0, m_s = -1/2$
$(c) n = 1, l = 1, m_l = 0, m_s = +1/2$
$(d) n = 2, l = 1, m_l = 0, m_s = -1/2$
$(e) n = 3, l = 3, m_l = 3, m_s = +1/2$
$(f) n = 3, l = 1, m_l = 0, m_s = +1/2$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A, C, E) The following sets of quantum numbers are not possible:
$(a) n = 0$ is not possible because the principal quantum number $n$ must be a positive integer $(n = 1, 2, 3, \dots)$.
$(c) n = 1, l = 1$ is not possible because for a given $n$,the azimuthal quantum number $l$ can only range from $0$ to $n-1$. Thus,if $n = 1$,$l$ must be $0$.
$(e) n = 3, l = 3$ is not possible because $l$ must always be less than $n$ $(l < n)$. Therefore,$l$ can only take values $0, 1, 2$ when $n = 3$.

Explore More

Similar Questions

Which electronic configuration represents a noble gas?

Two electrons occupying the same orbital are distinguished by

What is the electronic configuration of Chromium $(Z=24)$?

Which set of quantum numbers for an electron of an atom is not possible?

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination$(s)$ has/have the same energy,list them:
$(1).$ $n=4, l=2, m_l=-2, m_s=-1/2$
$(2).$ $n=3, l=2, m_l=1, m_s=+1/2$
$(3).$ $n=4, l=1, m_l=0, m_s=+1/2$
$(4).$ $n=3, l=2, m_l=-2, m_s=-1/2$
$(5).$ $n=3, l=1, m_l=-1, m_s=+1/2$
$(6).$ $n=4, l=1, m_l=0, m_s=+1/2$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo