Column-$I$ shows the electronic configuration of some elements and Column-$II$ shows the values of electron gain enthalpy. Match these values correctly. Match the electronic configuration with the electron gain enthalpy.

Column-$I$ Electronic Configuration	Column-$II$ Electron Gain Enthalpy / $kJ \ mol^{-1}$
$(A) \ 1s^2 2s^2 2p^6$	$(1) -53$
$(B) \ 1s^2 2s^2 2p^6 3s^1$	$(2) -328$
$(C) \ 1s^2 2s^2 2p^5$	$(3) -141$
$(D) \ 1s^2 2s^2 2p^4$	$(4) +53$

(A-4, B-1, C-2, D-3) The electron gain enthalpy values are determined by the stability of the electronic configuration:
$(A) \ 1s^2 2s^2 2p^6$ represents Neon (a noble gas),which has a stable octet configuration,so it has a positive electron gain enthalpy: $(+53 \ kJ \ mol^{-1})$. Thus,$(A-4)$.
$(B) \ 1s^2 2s^2 2p^6 3s^1$ represents Sodium,which has a low electron gain enthalpy: $(-53 \ kJ \ mol^{-1})$. Thus,$(B-1)$.
$(C) \ 1s^2 2s^2 2p^5$ represents Fluorine,which has a very high negative electron gain enthalpy: $(-328 \ kJ \ mol^{-1})$. Thus,$(C-2)$.
$(D) \ 1s^2 2s^2 2p^4$ represents Oxygen,which has an electron gain enthalpy of: $(-141 \ kJ \ mol^{-1})$. Thus,$(D-3)$.
Therefore,the correct match is $(A-4, B-1, C-2, D-3)$.