Show the dipole moment of $H_2O$ and $BeH_2$ with diagrams.

(N/A) $H_2O$ molecule is angular with a bond angle of $H-O-H$ equal to $104.5^{\circ}$.
$BeH_2$ molecule is linear with a bond angle of $H-Be-H$ equal to $180^{\circ}$.
In $H_2O$,the individual bond dipoles do not cancel each other,resulting in a net dipole moment of $\mu = 1.85 \ D$.
In $BeH_2$,the two $Be-H$ bond dipoles are equal in magnitude and opposite in direction,so they cancel each other out,resulting in a net dipole moment of $\mu = 0$.