Why is the bond angle in CH_4 not 90^{circ},e | vedclass

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(C) In $CH_4$,before bond formation,the $2s$ orbital and three $2p$ orbitals of carbon undergo $sp^3$ hybridization. This results in the formation of

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Due to $sp^3$ hybridization

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(C) In $CH_4$,before bond formation,the $2s$ orbital and three $2p$ orbitals of carbon undergo $sp^3$ hybridization. This results in the formation of four equivalent $sp^3$ hybrid orbitals directed towards the corners of a regular tetrahedron. Therefore,the bonds are not formed using the original $p$-orbitals at $90^{\circ}$,but rather through these $sp^3$ hybrid orbitals,resulting in a bond angle of $109.5^{\circ}$.

Why is the bond angle in $CH_4$ not $90^{\circ}$,even though the outermost $p$-orbitals of carbon are at $90^{\circ}$ to each other?

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