Between $NH_3$ and $N_2$,which one has a higher value of $(i) \ a$ and which one has a higher value of $(ii) \ b$? (Where $a$ and $b$ are van der Waals constants.)
- A$NH_3$ has higher $a$ and $N_2$ has higher $b$
- B$N_2$ has higher $a$ and $NH_3$ has higher $b$
- C$NH_3$ has higher $a$ and $NH_3$ has higher $b$
- D$N_2$ has higher $a$ and $N_2$ has higher $b$
Explore More
Similar Questions
Van der Waals equation for a gas is stated as,
$p = \frac{nRT}{V - nb} - a\left( \frac{n}{V} \right)^2$
This equation reduces to the perfect gas equation,$p = \frac{nRT}{V}$,when:
$p = \frac{nRT}{V - nb} - a\left( \frac{n}{V} \right)^2$
This equation reduces to the perfect gas equation,$p = \frac{nRT}{V}$,when:
DifficultJEE MAIN 2014
View SolutionAt a temperature of $27\,^{\circ}C$,if the volume of $2\, \text{moles}$ of $NH_3$ gas is $5\, L$ according to the van der Waals equation,what will be its pressure in $atm$? ($a = 4.17$,$b = 0.03711$)
Medium
View SolutionWhich of the following represents the $Van \ der \ Waals$ equation for $n$ moles of a real gas?
Easy
View SolutionStatement $-1$: The compressibility factor at the critical point is the same for different gases following van der Waal's equation.
Statement $-2$: The compressibility factor is independent of pressure at the critical temperature.
Statement $-2$: The compressibility factor is independent of pressure at the critical temperature.
Medium
View SolutionWhich of the following gas samples shows real gas behavior?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo