Industrially,$H_2O_2$ is prepared by the auto-oxidation of $2-alkylanthraquinols$.
$2-ethylanthraquinol \underset{H_2/Pd}{\overset{O_2 \text{ (air)}}{\rightleftarrows}} H_2O_2 + \text{oxidised product}$
In this process,$1\% H_2O_2$ is formed. It is extracted with water and concentrated to $\sim 30\%$ (by mass) by distillation under reduced pressure.
It can be further concentrated to $\sim 85\%$ by careful distillation under low pressure. The remaining water can be frozen out to obtain pure $H_2O_2$.
$(i)$ Oxidising effect in acidic medium:
$2Fe^{2+}_{(aq)} + 2H^+_{(aq)} + H_2O_{2(aq)} \longrightarrow 2Fe^{3+}_{(aq)} + 2H_2O_{(l)}$
$PbS_{(s)} + 4H_2O_{2(aq)} \longrightarrow PbSO_{4(s)} + 4H_2O_{(l)}$
$(ii)$ Reducing effect in acidic medium:
$2MnO_4^- + 6H^+ + 5H_2O_2 \longrightarrow 2Mn^{2+}_{(aq)} + 8H_2O + 5O_2$
$HOCl + H_2O_2 \longrightarrow H_3O^+ + Cl^- + O_2$
$(iii)$ Oxidising effect in basic medium:
$2Fe^{2+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2OH^-$
$Mn^{2+} + H_2O_2 \longrightarrow Mn^{4+} + 2OH^-$
$(iv)$ Reducing effect in basic medium:
$I_2 + H_2O_2 + 2OH^- \longrightarrow 2I^- + 2H_2O + O_2$
$2MnO_4^- + 3H_2O_2 \longrightarrow 2MnO_2 + 3O_2 + 2H_2O + 2OH^-$