The pH of 1 L of an aqueous solution of HCl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the initial solution: $pH_1 = 1$,so $[H^+]_1 = 10^{-pH_1} = 10^{-1} \ M$. Volume $V_1 = 1 \ L$. Number of moles of $H^+ = M_1 	imes V_1 = 10^

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) For the initial solution: $pH_1 = 1$,so $[H^+]_1 = 10^{-pH_1} = 10^{-1} \ M$. Volume $V_1 = 1 \ L$. Number of moles of $H^+ = M_1 	imes V_1 = 10^{-1} 	imes 1 = 0.1 \ mol$. For the final solution: $pH_2 = 2$,so $[H^+]_2 = 10^{-pH_2} = 10^{-2} \ M$. Let the final volume be $V_2$. Since the number of moles of $H^+$ remains constant: $M_1 	imes V_1 = M_2 	imes V_2$. $0.1 	imes 1 = 0.01 	imes V_2$. $V_2 = 10 \ L$. Volume of water to be added = $V_2 - V_1 = 10 \ L - 1 \ L = 9 \ L$.

The $pH$ of $1 \ L$ of an aqueous solution of $HCl$ is $1$. How many liters of water must be added to make the $pH$ of this solution $2$ (in $L$)?

Similar Questions

What is the concentration of hydrogen $[H^{+}]$ ions in $0.01 \, M \, HCl$?

What is the $pH$ of $0.005 \ M \ NaOH$ solution?

The $pH$ of $0.0001 \ N$ solution of $KOH$ will be

$40 \ mg$ of pure sodium hydroxide is dissolved in $10 \ L$ of distilled water. The $p^H$ of the solution is ..........

What is the $pH$ of a $0.005 \ M$ $Ba(OH)_2$ solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module