Match the type of hybridization of the carbon atom attached to the halogen in Column-$I$ with the hybridization type in Column-$II$.

Column-$I$ (Structure)	Column-$II$ (Hybridization)
$A$. $CH_3CH_2Cl$	$i$. $sp$
$B$. $CH_2=CHCl$	$ii$. $sp^2$
$C$. $CH_2=CH-CH_2Cl$	$iii$. $sp^3$
$D$. Chlorobenzene	$iv$. $sp^3d$

(A-III, B-II, C-III, D-II) To determine the hybridization of the carbon atom attached to the halogen:
$A$. $CH_3-CH_2-Cl$: The carbon attached to $Cl$ is bonded to one $C$ and two $H$ atoms (single bonds). It has $4$ sigma bonds,so it is $sp^3$ hybridized.
$B$. $CH_2=CH-Cl$: The carbon attached to $Cl$ is part of a double bond. It has $3$ sigma bonds,so it is $sp^2$ hybridized.
$C$. $CH_2=CH-CH_2-Cl$: The carbon attached to $Cl$ is bonded to one $C$ and two $H$ atoms (single bonds). It has $4$ sigma bonds,so it is $sp^3$ hybridized.
$D$. Chlorobenzene: The carbon attached to $Cl$ is part of the aromatic ring (double bond). It has $3$ sigma bonds,so it is $sp^2$ hybridized.
Therefore,the correct matching is: $(A-iii, B-ii, C-iii, D-ii)$.