Match the reactants in Column-$(I)$ with the products formed in Column-$(II)$.
Column-$(I)$ (Reactants) Column-$(II)$ (Major Products) $(A)$ $C_6H_5CH_3 + X_2 \xrightarrow{Fe, \text{dark}}$ $(i)$ $C_6H_5CH(Br)CH_3$ $(B)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 \ K}$ $(ii)$ $C_6H_5N_2^+X^-$ $(C)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2}$ $(iii)$ $p-X-C_6H_4CH_3 + o-X-C_6H_4CH_3$ $(D)$ $C_6H_5CH_2CH_3 \xrightarrow{Br_2, \Delta \text{ or } UV \text{ light}}$ $(iv)$ $C_6H_5X$
| Column-$(I)$ (Reactants) | Column-$(II)$ (Major Products) |
|---|---|
| $(A)$ $C_6H_5CH_3 + X_2 \xrightarrow{Fe, \text{dark}}$ | $(i)$ $C_6H_5CH(Br)CH_3$ |
| $(B)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 \ K}$ | $(ii)$ $C_6H_5N_2^+X^-$ |
| $(C)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2}$ | $(iii)$ $p-X-C_6H_4CH_3 + o-X-C_6H_4CH_3$ |
| $(D)$ $C_6H_5CH_2CH_3 \xrightarrow{Br_2, \Delta \text{ or } UV \text{ light}}$ | $(iv)$ $C_6H_5X$ |
(A-III, B-II, C-IV, D-I) $(A \rightarrow iii)$: Electrophilic aromatic substitution of toluene with $X_2$ in the presence of $Fe$ (dark) gives ortho and para halo-substituted toluene.
$(B \rightarrow ii)$: Aniline reacts with $NaNO_2$ and $HX$ at $273-278 \ K$ to form benzene diazonium salt.
$(C \rightarrow iv)$: Sandmeyer reaction of benzene diazonium salt with $Cu_2X_2$ yields aryl halide $(C_6H_5X)$.
$(D \rightarrow i)$: Free radical bromination of ethylbenzene with $Br_2$ under light/heat occurs at the benzylic position to form $1$-bromo-$1$-phenylethane.
$(B \rightarrow ii)$: Aniline reacts with $NaNO_2$ and $HX$ at $273-278 \ K$ to form benzene diazonium salt.
$(C \rightarrow iv)$: Sandmeyer reaction of benzene diazonium salt with $Cu_2X_2$ yields aryl halide $(C_6H_5X)$.
$(D \rightarrow i)$: Free radical bromination of ethylbenzene with $Br_2$ under light/heat occurs at the benzylic position to form $1$-bromo-$1$-phenylethane.
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Similar Questions
Correct statements regarding alkyl halides ($R-X$) among the following are:
A. Alcohol being less polar solvent as compared to water, alcoholic $KOH$ favours elimination reaction with $R-X$.
B. Order of reactivity towards $S_N1$ mechanism is $C_6H_5-CH_2-Cl > C_6H_5-CHCl-C_6H_5$.
C. Non substituted aryl halides exhibit properties similar to alkyl halides.
D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne.
E. $R-Cl$ can be prepared by reacting $R-OH$ with $SOCl_2$ but $Ar-Cl$ cannot be prepared by reacting $Ar-OH$ with $SOCl_2$.
Choose the correct answer from the options given below:
Which of the following is not formed in the given reaction?
$C_6H_5CH_2Cl + CH_3Cl \xrightarrow{Na, \text{dry ether}}$
$C_6H_5CH_2Cl + CH_3Cl \xrightarrow{Na, \text{dry ether}}$
Medium
View SolutionProduct $(A)$ in this sequence is:
Medium
View Solution$C_3H_7I$ $(P)$ $\xrightarrow[\text{alc. } KOH]{\Delta}$ $Q$ $\xrightarrow{NBS}$ $R$ $\xrightarrow{KCN}$ $CH_2 = CH - CH_2 - CN$. $P$ can be:
Medium
View SolutionComplete the following reactions:
$(1)$ $1$-Chloropropane $\xrightarrow[{KOH}]{{\text{ethanol}}} (B)$ $\xrightarrow[{CCl_4}]{{Br_2}} (C)$
$(2)$ Ethane $\xrightarrow[{hv}]{{Cl_2}} (B)$ $\xrightarrow[{Na, \text{ether}}]{} (C)$
$(1)$ $1$-Chloropropane $\xrightarrow[{KOH}]{{\text{ethanol}}} (B)$ $\xrightarrow[{CCl_4}]{{Br_2}} (C)$
$(2)$ Ethane $\xrightarrow[{hv}]{{Cl_2}} (B)$ $\xrightarrow[{Na, \text{ether}}]{} (C)$
Medium
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