Match the type of reaction given in Column-$I$ with the reaction in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Type of Reaction) $(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$ $(i)$ Wurtz-Fittig reaction $(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$ $(ii)$ Diazotization $(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$ $(iii)$ Sandmeyer reaction $(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$ $(iv)$ Fittig reaction
| Column-$I$ (Reactants) | Column-$II$ (Type of Reaction) |
|---|---|
| $(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$ | $(i)$ Wurtz-Fittig reaction |
| $(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$ | $(ii)$ Diazotization |
| $(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$ | $(iii)$ Sandmeyer reaction |
| $(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$ | $(iv)$ Fittig reaction |
(A-II, B-III, C-I, D-IV) The conversion of aniline to benzene diazonium salt is known as Diazotization $(ii)$.
$(B)$ The conversion of benzene diazonium salt to haloarene using $Cu_2X_2$ is known as the Sandmeyer reaction $(iii)$.
$(C)$ The reaction of an aryl halide with an alkyl halide in the presence of sodium and dry ether is the Wurtz-Fittig reaction $(i)$.
$(D)$ The coupling of two aryl halide molecules in the presence of sodium and dry ether is the Fittig reaction $(iv)$.
Therefore,the correct matching is: $(A-ii, B-iii, C-i, D-iv)$.
$(B)$ The conversion of benzene diazonium salt to haloarene using $Cu_2X_2$ is known as the Sandmeyer reaction $(iii)$.
$(C)$ The reaction of an aryl halide with an alkyl halide in the presence of sodium and dry ether is the Wurtz-Fittig reaction $(i)$.
$(D)$ The coupling of two aryl halide molecules in the presence of sodium and dry ether is the Fittig reaction $(iv)$.
Therefore,the correct matching is: $(A-ii, B-iii, C-i, D-iv)$.
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Similar Questions
Correct statements regarding alkyl halides ($R-X$) among the following are:
A. Alcohol being less polar solvent as compared to water, alcoholic $KOH$ favours elimination reaction with $R-X$.
B. Order of reactivity towards $S_N1$ mechanism is $C_6H_5-CH_2-Cl > C_6H_5-CHCl-C_6H_5$.
C. Non substituted aryl halides exhibit properties similar to alkyl halides.
D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne.
E. $R-Cl$ can be prepared by reacting $R-OH$ with $SOCl_2$ but $Ar-Cl$ cannot be prepared by reacting $Ar-OH$ with $SOCl_2$.
Choose the correct answer from the options given below:
How will you bring about the following conversions?
$(i)$ Ethanol to but$-1-$yne
$(ii)$ Ethane to bromoethene
$(iii)$ Propene to $1-$nitropropane
$(iv)$ Toluene to benzyl alcohol
$(v)$ Propene to propyne
$(vi)$ Ethanol to ethyl fluoride
$(vii)$ Bromomethane to propanone
$(viii)$ But$-1-$ene to but$-2-$ene
$(ix)$ $1-$Chlorobutane to $n-$octane
$(x)$ Benzene to biphenyl.
$(i)$ Ethanol to but$-1-$yne
$(ii)$ Ethane to bromoethene
$(iii)$ Propene to $1-$nitropropane
$(iv)$ Toluene to benzyl alcohol
$(v)$ Propene to propyne
$(vi)$ Ethanol to ethyl fluoride
$(vii)$ Bromomethane to propanone
$(viii)$ But$-1-$ene to but$-2-$ene
$(ix)$ $1-$Chlorobutane to $n-$octane
$(x)$ Benzene to biphenyl.
Easy
View SolutionGiven below are two statements:
Statement $I$: Due to increase in van der Waals forces, the order of boiling points is $CH_3CH_2CH_2I > CH_3CH_2I > CH_3I$.
Statement $II$: As $para$-dichlorobenzene is more symmetric, its melting point is higher than $ortho$-dichlorobenzene, however its boiling point is lower than $ortho$-dichlorobenzene.
In the light of the above statements, choose the correct answer from the options given below:
Statement $I$: Due to increase in van der Waals forces, the order of boiling points is $CH_3CH_2CH_2I > CH_3CH_2I > CH_3I$.
Statement $II$: As $para$-dichlorobenzene is more symmetric, its melting point is higher than $ortho$-dichlorobenzene, however its boiling point is lower than $ortho$-dichlorobenzene.
In the light of the above statements, choose the correct answer from the options given below:
The compound which is $NOT$ formed when a mixture of $n$-butyl bromide and ethyl bromide is treated with sodium metal in the presence of dry ether is:
What will be the final major product?
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