Find the enantiomers of the structures in Column-$(I)$ from Column-$(II)$.

Column-$(I)$	Column-$(II)$
$(A)$ $C_2H_5-C(CH_3)(OH)-H$	$(p)$ $Cl-C(Br)(I)-H$
$(B)$ $Br-C(Cl)(I)-H$	$(q)$ $OH-C(CH_3)(C_2H_5)-H$
	$(r)$ $H_5C_2-C(OH)(CH_3)-H$
	$(s)$ $Cl-C(I)(Br)-H$

(A-Q, B-S) Enantiomers are non-superimposable mirror images of each other.
For structure $(A)$,the chiral center is bonded to $-CH_3$,$-C_2H_5$,$-OH$,and $-H$. Its mirror image is $(q)$.
For structure $(B)$,the chiral center is bonded to $-Br$,$-Cl$,$-I$,and $-H$. Its mirror image is $(s)$.
Therefore,the correct matches are $(A)-(q)$ and $(B)-(s)$.