Match the reaction in Column-$I$ with the mechanism in Column-$II$.
Column-$I$ (Reaction)Column-$II$ (Mechanism)
$A$. $CH_3OCH_2CH_3 + HI \to CH_3I + CH_3CH_2OH$$i$. $S_{E}2$ Aromatic
$B$. $(CH_3)_3COCH_3 + HI \to CH_3OH + (CH_3)_3CI$$ii$. $S_{N}1$
$C$. $C_6H_5OCH_3 + Br_2(CH_3COOH) \to p$-Bromoanisole$iii$. Elimination $(\beta)$
$D$. $CH_3CH_2OH + H_2SO_4 (443 \ K) \to CH_2=CH_2$$iv$. $S_{N}2$

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(A-IV, B-II, C-I, D-III) The correct matches are as follows:
$A \to iv$: The reaction of primary alkyl ethers with $HI$ proceeds via an $S_{N}2$ mechanism.
$B \to ii$: The reaction of ethers containing a tertiary alkyl group with $HI$ proceeds via an $S_{N}1$ mechanism because a stable carbocation is formed.
$C \to i$: The bromination of anisole is an electrophilic aromatic substitution ($S_{E}2$ Aromatic) reaction.
$D \to iii$: The dehydration of ethanol to ethene in the presence of concentrated $H_2SO_4$ at $443 \ K$ is a $\beta$-elimination reaction.
Therefore,the correct sequence is: $A-iv, B-ii, C-i, D-iii$.

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Similar Questions

Write the chemical reactions for the following conversions:
$1.$ Phenol to Anisole and Phenetole
$2.$ Chlorobenzene to $p$-Bromoanisole

Match List-$I$ with List-$II$.
List-$I$List-$II$
$A$. Phenol $\rightarrow$ Salicylaldehyde$I$. $Br_2$ in $CS_2$
$B$. Phenol $\rightarrow$ Benzene$II$. $Na_2Cr_2O_7/H_2SO_4$
$C$. Phenol $\rightarrow$ $p$-Benzoquinone$III$. $Zn$
$D$. Phenol $\rightarrow$ $p$-Bromophenol$IV$. $CHCl_3/NaOH$

Choose the correct answer from the options given below:

Identify $B$ and $D$ in the following sequence of reactions.

Match the following:
Column-$I$: Compound / Reagent Column-$II$: Other name / Chemical / Process
$A$. Methanol $I$. Lucas reagent
$B$. $ZnCl_2$ / Conc. $HCl$ $II$. Baeyer's reagent
$C$. Rectified spirit $III$. Wood spirit
$D$. Dil. $KMnO_4$ $IV$. $95 \% C_2H_5OH$
- $V$. $75 \% C_2H_5OH$
- $VI$. $90 \% C_3H_7OH$

The correct match is:

The increasing order of boiling points of the following is:
MoleculeLabel
$CH_3-O-CH_3$$I$
$CH_3CHO$$II$
$CH_3CH_2CH_3$$III$
$CH_3CH_2OH$$IV$

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