The increasing order of boiling points of the | vedclass

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(B) To determine the boiling point order,we analyze the intermolecular forces present in each molecule:$1$. $CH_3CH_2CH_3$ $(III)$: This is an alkane,

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$III < I < II < IV$

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(B) To determine the boiling point order,we analyze the intermolecular forces present in each molecule:$1$. $CH_3CH_2CH_3$ $(III)$: This is an alkane,which only has weak London dispersion forces. It has the lowest boiling point.$2$. $CH_3-O-CH_3$ $(I)$: This is an ether,which has weak dipole-dipole interactions. Its boiling point is higher than the alkane but lower than polar molecules with stronger interactions.$3$. $CH_3CHO$ $(II)$: This is an aldehyde,which has stronger dipole-dipole interactions due to the polar $C=O$ bond.$4$. $CH_3CH_2OH$ $(IV)$: This is an alcohol,which exhibits strong intermolecular hydrogen bonding. It has the highest boiling point among these.Thus,the increasing order of boiling points is $III < I < II < IV$.

Molecule	Label
$CH_3-O-CH_3$	$I$
$CH_3CHO$	$II$
$CH_3CH_2CH_3$	$III$
$CH_3CH_2OH$	$IV$

Column-$I$ (Reaction)	Column-$II$ (Bond broken)
$(A)$ $RCH_2OH \xrightarrow{CrO_3} RCHO$	$(i)$ $C-O$ bond breaks.
$(B)$ Phenol $\xrightarrow{HNO_3}$ $p$-Nitrophenol + $o$-Nitrophenol	(ii) $O-H$ bond breaks.
$(C)$ Phenol + $NaOH \rightarrow$ Sodium phenoxide + $H_2O$	(iii) $O-H$ and $C-H$ bonds break.
$(D)$ $CH_3CH_2CH_2OH \xrightarrow{H_2SO_4, \Delta} CH_3CH=CH_2$	(iv) $C-H$ bond breaks.

Group-$I$ (Compound)	Group-$II$ (Use)
$A$. Alcohol	$1$. Antiseptic
$B$. Phenol	$2$. Perfumes
$C$. Ether	$3$. Detergents
$D$. Amine	$4$. Dyes

Column-$I$: Compound / Reagent	Column-$II$: Other name / Chemical / Process
$A$. Methanol	$I$. Lucas reagent
$B$. $ZnCl_2$ / Conc. $HCl$	$II$. Baeyer's reagent
$C$. Rectified spirit	$III$. Wood spirit
$D$. Dil. $KMnO_4$	$IV$. $95 \% C_2H_5OH$
-	$V$. $75 \% C_2H_5OH$
-	$VI$. $90 \% C_3H_7OH$

The increasing order of boiling points of the following is:
Molecule Label
$CH_3-O-CH_3$ $I$
$CH_3CHO$ $II$
$CH_3CH_2CH_3$ $III$
$CH_3CH_2OH$ $IV$

Similar Questions

Esterification of the acid $P$ with the alcohol $Q$ will give:

Match the compounds in Group-$I$ with their uses in Group-$II$. Find the correct match for Group-$I$ from Group-$II$.

Group-$I$ (Compound) Group-$II$ (Use)

$A$. Alcohol $1$. Antiseptic

$B$. Phenol $2$. Perfumes

$C$. Ether $3$. Detergents

$D$. Amine $4$. Dyes

The predominant intermolecular forces present in ethyl acetate,a liquid,are

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The increasing order of boiling points of the following is:MoleculeLabel$CH_3-O-CH_3$$I$$CH_3CHO$$II$$CH_3CH_2CH_3$$III$$CH_3CH_2OH$$IV$