Esterification of the acid $P$ with the alcohol $Q$ will give:
- Aonly one enantiomer
- Ba mixture of diastereomers
- Ca mixture of enantiomers
- Donly one diastereomer
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Similar Questions
$A$ new carbon-carbon bond formation is possible in
DifficultIIT 1998
View SolutionMatch the items given in column $-I$ with the items given in column $-II$.
column $-I$ column $-II$ $(A)$ Antifreeze used in car engine $(1)$ Neutral $FeCl_3$ $(B)$ Solvent used in perfumes $(2)$ Glycerol $(C)$ Starting material for picric acid $(3)$ Methanol $(D)$ Wood spirit $(4)$ Phenol $(E)$ Reagent used for detection of phenolic group $(5)$ Ethylene glycol $(F)$ By-product of soap industry used in cosmetics $(6)$ Ethanol
| column $-I$ | column $-II$ |
| $(A)$ Antifreeze used in car engine | $(1)$ Neutral $FeCl_3$ |
| $(B)$ Solvent used in perfumes | $(2)$ Glycerol |
| $(C)$ Starting material for picric acid | $(3)$ Methanol |
| $(D)$ Wood spirit | $(4)$ Phenol |
| $(E)$ Reagent used for detection of phenolic group | $(5)$ Ethylene glycol |
| $(F)$ By-product of soap industry used in cosmetics | $(6)$ Ethanol |
Medium
View SolutionMatch the reactants in Column-$I$ with the products formed in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Products) $A$. Cumene $+ O_2$ $i$. Phenol $B$. Benzene sulphonic acid $\xrightarrow{NaOH, H^+}$ $ii$. $2$-Methylbutan-$1$-ol $C$. Chlorobenzene $+ NaOH \xrightarrow{623 \ K, 300 \ atm}$ $iii$. Cumene hydroperoxide $D$. $2$-Methylbutanal $\xrightarrow{NaBH_4}$ $iv$. Sodium phenoxide
| Column-$I$ (Reactants) | Column-$II$ (Products) |
| $A$. Cumene $+ O_2$ | $i$. Phenol |
| $B$. Benzene sulphonic acid $\xrightarrow{NaOH, H^+}$ | $ii$. $2$-Methylbutan-$1$-ol |
| $C$. Chlorobenzene $+ NaOH \xrightarrow{623 \ K, 300 \ atm}$ | $iii$. Cumene hydroperoxide |
| $D$. $2$-Methylbutanal $\xrightarrow{NaBH_4}$ | $iv$. Sodium phenoxide |
Difficult
View SolutionMatch the following:
Column-$I$: Compound / Reagent Column-$II$: Other name / Chemical / Process $A$. Methanol $I$. Lucas reagent $B$. $ZnCl_2$ / Conc. $HCl$ $II$. Baeyer's reagent $C$. Rectified spirit $III$. Wood spirit $D$. Dil. $KMnO_4$ $IV$. $95 \% C_2H_5OH$ - $V$. $75 \% C_2H_5OH$ - $VI$. $90 \% C_3H_7OH$
The correct match is:
| Column-$I$: Compound / Reagent | Column-$II$: Other name / Chemical / Process |
|---|---|
| $A$. Methanol | $I$. Lucas reagent |
| $B$. $ZnCl_2$ / Conc. $HCl$ | $II$. Baeyer's reagent |
| $C$. Rectified spirit | $III$. Wood spirit |
| $D$. Dil. $KMnO_4$ | $IV$. $95 \% C_2H_5OH$ |
| - | $V$. $75 \% C_2H_5OH$ |
| - | $VI$. $90 \% C_3H_7OH$ |
The correct match is:
DifficultTS EAMCET 2021
View SolutionMatch the reactions given in Column-$I$ with the conditions given in Column-$II$.
Column-$I$ (Reaction) Column-$II$ (Condition) $(A)$ $CH_3-CH(OH)-CH_3 \rightarrow CH_3-CH=CH_2$ $(i)$ $20\% \ H_3PO_4, 358 \ K$ $(B)$ $CH_3-C(CH_3)_2-OH \rightarrow CH_3-C(CH_3)=CH_2$ (ii) $Cu, 573 \ K$ $(C)$ $CH_3CH_2OH \rightarrow CH_2=CH_2 + H_2O$ (iii) $85\% \ H_3PO_4, 440 \ K$ $(D)$ $R-CH(OH)-R' \rightarrow R-CO-R'$ (iv) $H_2SO_4, 443 \ K$
| Column-$I$ (Reaction) | Column-$II$ (Condition) |
|---|---|
| $(A)$ $CH_3-CH(OH)-CH_3 \rightarrow CH_3-CH=CH_2$ | $(i)$ $20\% \ H_3PO_4, 358 \ K$ |
| $(B)$ $CH_3-C(CH_3)_2-OH \rightarrow CH_3-C(CH_3)=CH_2$ | (ii) $Cu, 573 \ K$ |
| $(C)$ $CH_3CH_2OH \rightarrow CH_2=CH_2 + H_2O$ | (iii) $85\% \ H_3PO_4, 440 \ K$ |
| $(D)$ $R-CH(OH)-R' \rightarrow R-CO-R'$ | (iv) $H_2SO_4, 443 \ K$ |
Medium
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