A and B can do a work in 12 days. B and C can | vedclass

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(B) $(A+B)$'s $1$ day's work $= \frac{1}{12}$ .....$(i)$$(B+C)$'s $1$ day's work $= \frac{1}{15}$ .....$(ii)$$(C+A)$'s $1$ day's work $= \frac{1}{20}$

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) $(A+B)$'s $1$ day's work $= \frac{1}{12}$ .....$(i)$$(B+C)$'s $1$ day's work $= \frac{1}{15}$ .....$(ii)$$(C+A)$'s $1$ day's work $= \frac{1}{20}$ .....$(iii)$Adding equations $(i), (ii),$ and $(iii)$:$2(A+B+C)$'s $1$ day's work $= \frac{1}{12} + \frac{1}{15} + \frac{1}{20} = \frac{5+4+3}{60} = \frac{12}{60} = \frac{1}{5}$Therefore,$(A+B+C)$'s $1$ day's work $= \frac{1}{5 	imes 2} = \frac{1}{10}$Thus,the time taken by $A, B,$ and $C$ together to complete the work is $10$ days.

$A$ and $B$ can do a work in $12$ days. $B$ and $C$ can do the same work in $15$ days. $C$ and $A$ can do the same work in $20$ days. How much time will $A, B,$ and $C$ take to complete the same work together (in days)?

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