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Question

(B) Given that $4$ men,$6$ women,or $10$ children can paint a house in $5$ days.Work done by $1$ man in $1$ day $= \frac{1}{4 	imes 5} = \frac{1}{20}

Vedclass · Accepted Answer

$5 \frac{5}{11}$

Vedclass · Answer

(B) Given that $4$ men,$6$ women,or $10$ children can paint a house in $5$ days.Work done by $1$ man in $1$ day $= \frac{1}{4 	imes 5} = \frac{1}{20}$ of the house.Work done by $1$ woman in $1$ day $= \frac{1}{6 	imes 5} = \frac{1}{30}$ of the house.Work done by $1$ child in $1$ day $= \frac{1}{10 	imes 5} = \frac{1}{50}$ of the house.The group consists of a couple (a man and a woman) and $5$ sons (children).Total work done by them in $1$ day $= 1 	imes (\frac{1}{20}) + 1 	imes (\frac{1}{30}) + 5 	imes (\frac{1}{50})$$= \frac{1}{20} + \frac{1}{30} + \frac{1}{10} = \frac{3 + 2 + 6}{60} = \frac{11}{60}$.Time required to finish the work $= \frac{1}{\frac{11}{60}} = \frac{60}{11} = 5 \frac{5}{11}$ days.

$4$ men or $6$ women or $10$ children can paint a house in $5$ days. The painting is given to a couple (a man and a woman) and their $5$ sons. They finish the job in (in days):

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