2 men and 3 women can complete a work in 10 d | vedclass

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(B) Let $M$ be the work done by $1$ man in $1$ day and $W$ be the work done by $1$ woman in $1$ day.From the given information:$10(2M + 3W) = 1$ (Tota

Vedclass · Accepted Answer

$8$

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(B) Let $M$ be the work done by $1$ man in $1$ day and $W$ be the work done by $1$ woman in $1$ day.From the given information:$10(2M + 3W) = 1$ (Total work)$10(4M) = 1$ (Total work)Equating the two: $10(4M) = 10(2M + 3W) \Rightarrow 4M = 2M + 3W \Rightarrow 2M = 3W$.Thus,$1$ man's work is equivalent to $1.5$ women's work.From $4M$ in $10$ days,total work $= 40$ man-days.We need to find the time for $3$ men and $3$ women.Since $2M = 3W$,$3$ men $+ 3$ women $= 3$ men $+ 2$ men $= 5$ men.Using the formula $M_1 D_1 = M_2 D_2$:$4 	ext{ men} 	imes 10 	ext{ days} = 5 	ext{ men} 	imes D_2 	ext{ days}$.$D_2 = \frac{40}{5} = 8$ days.

$2$ men and $3$ women can complete a work in $10$ days,while $4$ men can complete it in $10$ days. In how many days will $3$ men and $3$ women complete the work?

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