A can finish a work in 24 , days,B in 9 , day | vedclass

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(C) Work done by $A$ in $1 \, day = \frac{1}{24}$.Work done by $B$ in $1 \, day = \frac{1}{9}$.Work done by $C$ in $1 \, day = \frac{1}{12}$.Work done

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$10$

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(C) Work done by $A$ in $1 \, day = \frac{1}{24}$.Work done by $B$ in $1 \, day = \frac{1}{9}$.Work done by $C$ in $1 \, day = \frac{1}{12}$.Work done by $B$ and $C$ together in $1 \, day = \frac{1}{9} + \frac{1}{12} = \frac{4+3}{36} = \frac{7}{36}$.Work done by $B$ and $C$ in $3 \, days = 3 	imes \frac{7}{36} = \frac{7}{12}$.Remaining work $= 1 - \frac{7}{12} = \frac{5}{12}$.Let $A$ take $x$ days to complete the remaining work.$x 	imes \frac{1}{24} = \frac{5}{12}$.$x = \frac{5}{12} 	imes 24 = 10 \, days$.

$A$ can finish a work in $24 \, days$,$B$ in $9 \, days$,and $C$ in $12 \, days$. $B$ and $C$ start the work but are forced to leave after $3 \, days$. The remaining work was done by $A$ in (in $days$):

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